![The radius of the circle of sphere ${x^2} + {y^2} + {z^2} = 49$ and plane $2 x + 3y - z - 5\\sqrt {14} = 0$ is A. $\\sqrt 6 $B. $2\\sqrt 6 $C. $4\\sqrt 6 $D. None of these The radius of the circle of sphere ${x^2} + {y^2} + {z^2} = 49$ and plane $2 x + 3y - z - 5\\sqrt {14} = 0$ is A. $\\sqrt 6 $B. $2\\sqrt 6 $C. $4\\sqrt 6 $D. None of these](https://www.vedantu.com/question-sets/b64f86dd-f313-4040-82b5-605c0e7da8fa490534837074044279.png)
The radius of the circle of sphere ${x^2} + {y^2} + {z^2} = 49$ and plane $2 x + 3y - z - 5\\sqrt {14} = 0$ is A. $\\sqrt 6 $B. $2\\sqrt 6 $C. $4\\sqrt 6 $D. None of these
![The region in space with x^2 + y^2 + z^2≤R^2 and z < 0 has uniform volume charge density p. If the electric field at a point (0,0,R/2) is E.then the electric The region in space with x^2 + y^2 + z^2≤R^2 and z < 0 has uniform volume charge density p. If the electric field at a point (0,0,R/2) is E.then the electric](https://dwes9vv9u0550.cloudfront.net/images/3682110/71d27486-af5c-4274-90eb-0c4c720ec2e6.jpg)
The region in space with x^2 + y^2 + z^2≤R^2 and z < 0 has uniform volume charge density p. If the electric field at a point (0,0,R/2) is E.then the electric
![If x2 + y2 + z2 = r2, then a)πb)π/2c)0d)None of theseCorrect answer is option 'B'. Can you explain this answer? | EduRev JEE Question If x2 + y2 + z2 = r2, then a)πb)π/2c)0d)None of theseCorrect answer is option 'B'. Can you explain this answer? | EduRev JEE Question](https://edurev.gumlet.io/ApplicationImages/Temp/4041788_b9ddac4a-6ede-4d3b-a44f-ceb8298a35e7_lg.png)
If x2 + y2 + z2 = r2, then a)πb)π/2c)0d)None of theseCorrect answer is option 'B'. Can you explain this answer? | EduRev JEE Question
![multivariable calculus - Issues in calculating the volume bounded by cylinders $x^2 + y^2 = r^2$ and $z^2 + y^2 = r^2$ - Mathematics Stack Exchange multivariable calculus - Issues in calculating the volume bounded by cylinders $x^2 + y^2 = r^2$ and $z^2 + y^2 = r^2$ - Mathematics Stack Exchange](https://i.stack.imgur.com/VZDOq.jpg)