If the pairs of lines x^2+2xy+ay^2=0 and ax^2+2xy+y^2=0 have exactly one line in common then the joint equation of the other two lines is given by1) 3x^2+8xy 3y^2=0 2) 3x^2+10xy+3y^2=03) y^2+2xy 3x^2=0
![Q3 | If x^2 + 2xy + y^3 = 4 find dy/dx | Implicit Function | Differentiation | If x2 + 2xy + y3 = 4 - YouTube Q3 | If x^2 + 2xy + y^3 = 4 find dy/dx | Implicit Function | Differentiation | If x2 + 2xy + y3 = 4 - YouTube](https://i.ytimg.com/vi/i_EhLRluIvA/maxresdefault.jpg)
Q3 | If x^2 + 2xy + y^3 = 4 find dy/dx | Implicit Function | Differentiation | If x2 + 2xy + y3 = 4 - YouTube
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2 + - Brainly.com
![calculus - use implicit differentiation to find the derivative of $(x^2+y^2 )^4=6x^2y\,$? - Mathematics Stack Exchange calculus - use implicit differentiation to find the derivative of $(x^2+y^2 )^4=6x^2y\,$? - Mathematics Stack Exchange](https://i.stack.imgur.com/pTsw8.png)
calculus - use implicit differentiation to find the derivative of $(x^2+y^2 )^4=6x^2y\,$? - Mathematics Stack Exchange
![Calculus Help: Separable Differential Equations: 2xy+6x+(x^2-4) y' = 0 - Integration Factor - Steps - YouTube Calculus Help: Separable Differential Equations: 2xy+6x+(x^2-4) y' = 0 - Integration Factor - Steps - YouTube](https://i.ytimg.com/vi/XLCH4M7KjNI/hqdefault.jpg)
Calculus Help: Separable Differential Equations: 2xy+6x+(x^2-4) y' = 0 - Integration Factor - Steps - YouTube
![calculus - Show slopes of tangent lines to curve $2x^2 - 2xy + y^2 = 4$ at two points where it crosses the x-axis & y-axis are same. - Mathematics Stack Exchange calculus - Show slopes of tangent lines to curve $2x^2 - 2xy + y^2 = 4$ at two points where it crosses the x-axis & y-axis are same. - Mathematics Stack Exchange](https://i.stack.imgur.com/4uRjs.jpg)
calculus - Show slopes of tangent lines to curve $2x^2 - 2xy + y^2 = 4$ at two points where it crosses the x-axis & y-axis are same. - Mathematics Stack Exchange
![SOLVED: Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x^2 + 2xy − y^2 + x = 6, (2, 4) (hyperbola) SOLVED: Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x^2 + 2xy − y^2 + x = 6, (2, 4) (hyperbola)](https://cdn.numerade.com/ask_previews/5160c53f-8133-42de-9799-c3f566010f8b_large.jpg)