SOLVED: Show that the shortest distance D from the origin to the plane a x+b y+ c z=d is given by the formula: D=(|d|)/(√(a^2+b^2+c^2))
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SOLVED: The distance between the parallel planes ax + by + cz + d1 = 0 and ax + by + cz + d2 = 0 is D = |d1 − d2
