Equation sin 7x + cos 2x = 2 Solution is A) x=(2kpi)/7 + 3pi/14,kI B) x=npi + pi/4 , n I C)x= 2npi + pi/2 ,n I D)none of these
![SOLVED: (3Opt) Pi can be computed by adding the following terms 00 (-)k 4 4 4 T =4C = + 3 5 +9 K6 2k + 1 11 Write a function Piln) SOLVED: (3Opt) Pi can be computed by adding the following terms 00 (-)k 4 4 4 T =4C = + 3 5 +9 K6 2k + 1 11 Write a function Piln)](https://cdn.numerade.com/ask_images/b974a7bebdfa42c9ae586ce11c48bb8c.jpg)
SOLVED: (3Opt) Pi can be computed by adding the following terms 00 (-)k 4 4 4 T =4C = + 3 5 +9 K6 2k + 1 11 Write a function Piln)
![Trigonometry: Notation] Why is it pi + k pi and not pi + 2k pi? How do I know which one to use? : r/HomeworkHelp Trigonometry: Notation] Why is it pi + k pi and not pi + 2k pi? How do I know which one to use? : r/HomeworkHelp](https://i.redd.it/u7cjdtkkgrd91.jpg)
Trigonometry: Notation] Why is it pi + k pi and not pi + 2k pi? How do I know which one to use? : r/HomeworkHelp
![Trigonometry: Notation] Why is it pi + k pi and not pi + 2k pi? How do I know which one to use? : r/HomeworkHelp Trigonometry: Notation] Why is it pi + k pi and not pi + 2k pi? How do I know which one to use? : r/HomeworkHelp](https://preview.redd.it/trigonometry-notation-why-is-it-pi-k-pi-and-not-pi-2k-pi-v0-u7cjdtkkgrd91.jpg?width=640&crop=smart&auto=webp&s=bdf7051fa9ff7ac15d91b45ff5e8bb8f60fcbbcf)
Trigonometry: Notation] Why is it pi + k pi and not pi + 2k pi? How do I know which one to use? : r/HomeworkHelp
![trigonometry - If $z = cis(2k\pi/5)$, $z \neq 1$, then what is $(z+1/z)^2+(z^2 + 1/z^2)^2=$? - Mathematics Stack Exchange trigonometry - If $z = cis(2k\pi/5)$, $z \neq 1$, then what is $(z+1/z)^2+(z^2 + 1/z^2)^2=$? - Mathematics Stack Exchange](https://i.stack.imgur.com/1TSYa.png)
trigonometry - If $z = cis(2k\pi/5)$, $z \neq 1$, then what is $(z+1/z)^2+(z^2 + 1/z^2)^2=$? - Mathematics Stack Exchange
![trigonometry - How prove $\left(\sum\cos{\frac{2k-1}{p}\pi }\right)\cdot\left(\sum\cos{\frac{2k-1}{p}\pi}\right)$ - Mathematics Stack Exchange trigonometry - How prove $\left(\sum\cos{\frac{2k-1}{p}\pi }\right)\cdot\left(\sum\cos{\frac{2k-1}{p}\pi}\right)$ - Mathematics Stack Exchange](https://i.stack.imgur.com/5IciQ.jpg)